Question

A bus at a uniform speed covers a distance of 140 whole 2/3km in 4 whole 1/3 hours . Find the speed of the bus and the distance covered in 6 whole 1/2 hours

Answer 1

Avg. Speed of bus = total distance traveled / total time taken
total distance traveled = 140 2/3 = 422/3 = 140.667 km
total time taken = 4 1/3 = 13/3 =4.3333 hr
Avg. Speed of bus = 140.667 / 4.332 = 32.46 km/hr
Distance covered in 6 1/2 hours = 32.46 x 6.5 = 211 km

Answer 2

Answer:

The distance covered by bus = 211 Km

Step-by-step explanation:

$\text{Distance covered by the bus with uniform speed = }140\tfrac{2}{3}\:\:Km= \frac{422}{3}\:\:Km\\\\\text{Time taken by the bus = }4\tfrac{1}{3}\:\:Hours=\frac{13}{3}\:\:Hours\\\\\text{Speed of the bus = }\frac{Distance}{Time}=\frac{\frac{422}{3}}{\frac{13}{3}}=\frac{422}{3}\times \frac{3}{13}\\\\\implies\text{Speed of the bus = }\frac{422}{13}\text{ Km/hour}$

$\text{Time taken to travel the distance = }6\tfrac{1}{2}\:\:Hours = \frac{13}{2}\:\:Hours$

$\text{distance covered = }Time \times Speed = \frac{13}{2}\times \frac{422}{13}=211\:\:Km$

Therefore, The distance covered by bus = 211 Km