a bus at a unifprm speed covers a distance of 140 2/3 km in 4 1/3 hours. find the speed of the bus and the distance covered in 6 1/2 hours.
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Answer: Avg. Speed of bus = total distance traveled / total time taken
total distance traveled = 140 2/3 = 422/3 = 140.667 km
total time taken = 4 1/3 = 13/3 =4.3333 hr
Avg. Speed of bus = 140.667 / 4.332 = 32.46 km/hr
Distance covered in 6 1/2 hours = 32.46 x 6.5 = 211 km
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