Question

A bus begins to move with an acceleration of 1 m/s^2. A man who is 48 m behind the bus starts running at 10 m/s to catch the bus . The man will be able to catch the bus after

Answer 1

distance to be covered=48m
acceleration for "man" can be supposed -1m/s^2.
initial speed=10mps
48=10t-1/2(-1)t^2
t^2+20t-96=0
(t-8)(t-12)=0
t=8,12