A bus begins to move with an acceleration of 1 m/s2. A boy who is 48 m behind the bus starts running at 10 m/s towards the bus. After what time bus will cross the boy?
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Distance travelled by bus = Distance travelled by man - 48
so 1/2 X 1 Xt2 = 10t - 48
t2 - 20t + 96 = 0
t = 8sec, 12 sec
earlier time is 8 seconds
so 1/2 X 1 Xt2 = 10t - 48
t2 - 20t + 96 = 0
t = 8sec, 12 sec
earlier time is 8 seconds
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