Question

A bus can carry 58 passengers in a trip how many passengers will be carry in 181 days if it makes 8trips a day

Answer 1

No. of passengers that can be carried in one day = 58 × 8 = 464 (8 trips in one day

No. of passengers that can be carried in 181 days = 181 × 464 = 83,984

Answer = 83,984 passengers.

Mark me as the brainleist.

Answer 2

Answer:

83,984 passengers can be carried

Step-by-step explanation:

In one trip the bus can carry 58 passengers

In one day it makes eight trips

Number of trips made in 181 days = 181 × 8

Number of trips made in 181 days = 1448 trips

Number of passengers carried in 1448 trips = 1448 × Number of passengers carried in one trip

Number of passengers carried in 1448 trips = 1448 × 58

Number of passengers carried in 1448 trips = 83,984

The bus can carry 83,984 passengers in 181 days if it makes 8 trips a day