Question

A bus can ferry a maximum of 45 students. By setting up an inequality, find the
minimum number of buses that are needed to ferry 520 students.​

Answer 1

Given:

Maximum number of students that a bus can ferry = 45

Number of total students to be ferried = 520

To find:

Minimum number of buses required to ferry 520 students.

Solution:

Let the number of buses required to ferry 520 students be x.

Total number of students that these x buses can carry is less that 45:

520/x ≤ 45

Or total number of students to be ferried is 520, so 45x ≥ 520

⇒ x ≥ 520/45

x ≥ 11.56

Since x should not be in fraction, therefore the next whole number would be considered which is 12.

Therefore 12 buses would be required to ferry 520 students.

Answer 2

Answer:

520 divided by 45 = 11

45 x 11 = 495 so the remainder is 25 students

there is no way you're gonna leave the 25 students behind..so you have to order 12 bus.

Step-by-step explanation: