A bus covers 630km in 9h.If it completes the first two thirds of the journey at 60km/h.Calculate its speed for rest of the journey
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Answered by
1
Total distance =630 Km
Time taken = 9 hrs
2/3 rd of journey means 6 hrs .
Speed for 2/3 rd journey = 60 km/h
Distance = speed x time
= 60 x 6
= 360 km
Distance to be covered in 1/3 rd journey = 630 - 360 =270 km
Time = 3hr
Therefore speed for rest of the journey,
speed = 270/3 ( distance/time)
= 90 km/h
Answered by
1
90km/h
bec 2/3of journey is=2/3×9=6h
which means 60km/h×6=360km is covered in first 6 hours.....
we have to find apeed of rest 3 h
630-360=270
270/3
=90km /h
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