a bus covers a distance of 250 kilometres from Delhi to Jaipur in 5 hours and returns to Delphic in 4 hours calculate the average speed
Answers
Answer:
del to jaipur=250/5km=50
and in return journey=250/4km=62.5
avg speed=(50+62.5)÷2
Answer:
Average velocity of the bus = 55.5 km/h
Step by step explanations :
Given that,
a bus covers a distance of 250 kilometres from Delhi to Jaipur in 5 hours
Here we have,
Distance between Delhi to jaypur
= 250 km
Time taken in going Jaypur = 5 hours
Then speed of bus while going to jaypur = 250/5
= 50 km/h
Now,
Time taken in coming from Jaipur
= 4 hours
So,
Speed of the bus while coming from Jaipur = 250/4
= = 62.5 km/h
Now,
Average velocity =
First method
total distance covered/total time taken
Total distance covered = 250 × 2
= 500 km
Total time taken = 5 + 4
= 9 h
Average velocity = 500/9
= 55.5 km/h
Second method
When the velocities (V1 and V2) are given then
Average velocity = 2V1V2/(V1 + V2)
Here,
V1 = 50 km/h
V2 = 62.5 km/h
Putting the values,
2(50)(62.5)/(50 + 62.5)
= 6250/112.5
= 55.5 km/h