Physics, asked by parth214425, 11 months ago

a bus covers a distance of 250 kilometres from Delhi to Jaipur in 5 hours and returns to Delphic in 4 hours calculate the average speed​

Answers

Answered by sandipkdde
49

Answer:

del to jaipur=250/5km=50

and in return journey=250/4km=62.5

avg speed=(50+62.5)÷2

Attachments:
Answered by deepsen640
78

Answer:

Average velocity of the bus = 55.5 km/h

Step by step explanations :

Given that,

a bus covers a distance of 250 kilometres from Delhi to Jaipur in 5 hours

Here we have,

Distance between Delhi to jaypur

= 250 km

Time taken in going Jaypur = 5 hours

Then speed of bus while going to jaypur = 250/5

= 50 km/h

Now,

Time taken in coming from Jaipur

= 4 hours

So,

Speed of the bus while coming from Jaipur = 250/4

= = 62.5 km/h

Now,

Average velocity =

First method

total distance covered/total time taken

Total distance covered = 250 × 2

= 500 km

Total time taken = 5 + 4

= 9 h

Average velocity = 500/9

= 55.5 km/h

Second method

When the velocities (V1 and V2) are given then

Average velocity = 2V1V2/(V1 + V2)

Here,

V1 = 50 km/h

V2 = 62.5 km/h

Putting the values,

2(50)(62.5)/(50 + 62.5)

= 6250/112.5

= 55.5 km/h

__________

Average Velocity of the bus

= 55.5km/h

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