A bus covers a distance of 30 km during the first hour of its motion, 40 km during the second hour of its motion and 26 km during the third hour of its motion. Calculate the average speed and velocity.
Answers
Answer:
average speed = distance/ time
distance = (30 + 40 + 26) km = 96 km
time 3 hr
average speed 96 km/3 hr = 32 km/hr
average velocity = displacement/ time
From the given information, the motion appears in straight line
without changing any direction.
hence displacement and distance are equal
Hence average velocity 32 km/hr
Answer:
average speed = average velocity = 32 kmph
Explanation:
average speed = (total distance travelled)/(total time taken)
total distance travelled = 30+40+26 = 9km
total time taken = 1+1+1 = 3 hours
∴ average speed = (total distance travelled)/(total time taken) = 96/3
= 32 kmph
∵ directions were not mentioned, it was to be considered that bus travels in a straight line part in same direction
in such case, average velocity = average speed
⇒ average velocity = 32 kmph