a bus covers a distance of 600km at a certain speed. if its speed is 15km/h more than the original speed, it covers the distance in 2 hours less time.what is its initial speed?
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let speed of bus is x and time taken by bus is y
now
600/x=y----(1)
600/(x+15)=y-2 ------(2)
solve these two equation
600 {1/x-1/(x+15)}=2
600(15)=2(x^2+15x)
4500=x^2+15x
x^2+15x-4500=0
now solve quadratic equation
x=60km/h
hence bus initial speed is 60km/h
now
600/x=y----(1)
600/(x+15)=y-2 ------(2)
solve these two equation
600 {1/x-1/(x+15)}=2
600(15)=2(x^2+15x)
4500=x^2+15x
x^2+15x-4500=0
now solve quadratic equation
x=60km/h
hence bus initial speed is 60km/h
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