Question

a bus covers half distance at a speed of 4m/s and the remaining half at 6m/s . what is the average speed of the bus ?​

Answer 1

Explanation:

Average Speed = (V1+V2)/2= 4+6/2=5 ms^-1

Answer 2

Bus covers half a distance =4m/s

Bus covers other half a distance=6m/s

Average speed of the bus=

4 + 6 \div 2 = 5m \: per \: sec4+6÷2=5mpersec