a bus deacrease it's speed from 80km/h 60 km/h in 5 seconds find its acceleration
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Initial velocity,u=80km/h=80×5/18=22.22m/s
Final velocity, v=60km/h=60×5/18=16.66m/s
Time=5 s
Acceleration =v-u/t=16.66-22.22/5=-1.11m/s
Final velocity, v=60km/h=60×5/18=16.66m/s
Time=5 s
Acceleration =v-u/t=16.66-22.22/5=-1.11m/s
shinty1:
Thank you
Answered by
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howdy !!!
your answer is ----
Given, initial velocity u = 80km/h or 200/9 m/s
& final velocity v = 60km/h or 50/3 m/s
and , time period t = 5s
therefore, a = v-u/t
= 50/3-200/9/5
=> a = -50/5/9 = -1.11m/s^2
hope it help you ★
your answer is ----
Given, initial velocity u = 80km/h or 200/9 m/s
& final velocity v = 60km/h or 50/3 m/s
and , time period t = 5s
therefore, a = v-u/t
= 50/3-200/9/5
=> a = -50/5/9 = -1.11m/s^2
hope it help you ★
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