Math, asked by pv057966, 7 months ago

a bus deceases its speed from 80km/h to 40 km/h by 5 sec. find the acceleration of bus

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Answered by monjyotiboro

Answer:

Initial speed u=80 km/h=80×185=22.22 m/s

Final speed v=60 km/h=60×185=16.67 m/s

Using v=u+at

Or 16.67=22.22+α×5

⟹ a=−1.1 m/s

Step-by-step explanation:

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Answered by tannuharshul22

Answer:-

Initial speed of the bus,

u=80km/h

=18×1000/3600s

=1800m/36s.

Final speed of the bus,

v=60km/h

=60×1000/3600s

=600m/36s

Therefore,

acceleration=(v-u)/t

=(600/36 - 800/36)/5

Take LCM and solve.

= -10/9ms*2

= -1.11ms*2

so,the bus is decelerating at the rate of -1.11 ms*2

Hope it will help you

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a bus deceases its speed from 80km/h to 40 km/h by 5 sec. find the acceleration of bus​

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a bus deceases its speed from 80km/h to 40 km/h by 5 sec. find the acceleration of bus