A bus decrease it's speed from 80km/h to 60km/h in 10 sec. find the acceleration of the bus. Also find the distance covered by bus
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Answered by
0
v=80km/h
=80×100/3600
=2.23m/s
u=60km/h
=60×100/3600
=1.67m/s
t =10 s
a= v-u/t
= 2.23-1.67/10
= 2.063 m/s square.
=80×100/3600
=2.23m/s
u=60km/h
=60×100/3600
=1.67m/s
t =10 s
a= v-u/t
= 2.23-1.67/10
= 2.063 m/s square.
Loveyoukavudamalya:
You have to also find the distance
Answered by
1
Given:
Initial velocity(u) =80km\h
=80×5|18
=22.2 m/s
Final velocity(v) = 60km/h
=60×5/18
=16.6m/s
Time=10s
A=v-u/t
=16.6-22.2/10
=166×22.2
=3685.2
S=ut+1/2atsquare
=22.2×10+1/2×3685.2×10×10
=222+1/2×368520
=184482
Hope this really helps you
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