Question

A bus decrease its speed 90km/h to 36km/h in 4s. Find its acceleration.​

Answer 1

Answer:

Explanation:U (initial velocity)=90km/hr=25m/s

V(final velocity)=36km/hr=10m/S

ACCELERATION= V-U/T

=>. 25-10/4=15/4= 3.75m/s^2

Therefore acceleration is 3.75m/s^2

Answer 2

Explanation:

Initial Velocity(u) =>90km/h = 25m/s

Final Velocity(v) => 36km/h = 10m/s

Therefore, Acceleration = v-u/t

=> 25-10/4 = 15/4

= 3.75m/s^2

Hence, acceleration = 3.75m/s^2.