Physics, asked by jshristi617, 4 hours ago

a bus decrease its speed from 40 km/hr to 30 km/hr in 2 sec find acceleration​

Answers

Answered by BrainlyTwinklingstar
18

Given :

Initial velocity of the bus : 40 km/hr

Final velocity of the bus : 30 km/hr

Time taken : 2 sec

To find :

The acceleration of the bus.

Solution :

Firstly we have to convert km/hr to m/s

we know that,

» 1km/hr = 5/18km/hr

» 40km/hr = 40 × 5/18 = 11.1 m/s

» 30km/hr = 30 × 5/18 = 8.3 m/s

Accerlation is the rate of change of velocity.

  • It is a vector quantity having both magnitude as well as direction.
  • SI unit of acceleration is metre per second square.

As we are provided with initial velocity, final velocity and time we can use first equation of kinematics that is,

v = u + at

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • t denotes time taken

by substituting all the given values in the formula,

➝ v = u + at

➝ 8.3 = 11.1 + a(2)

➝ 2a = 8.3 - 11.1

➝ 2a = -2.8

➝ a = - 2.8/2

➝ a = - 1.4 m/s²

Thus, the acceleration of the bus is -1.4 m/s².

If the speed is decreasing with time then accerlation is negative. The negative accerlation is called deceleration or retardation.

\:

Know more :

First equation of kinematics : v = u + at

Second equation of kinematics : s = ut + 1/2at²

Third equation of kinematics : v² - u² = 2as

Answered by CopyThat
43

Answer:

  • -1.39 m/s² is the acceleration of the bus.

Explanation:

We have,

  • Initial velocity (u) = 40 Km/h
  • Final velocity (v) = 30 Km/h
  • Time taken (t) = 2 sec

To find,

  • Acceleration (a)

Solution,

>> Initial velocity (u):

=> 40 × 5/18

  • 11.11 m/s

____________________

>> Final velocity (v):

=> 30 × 5/18

  • 8.33 m/s

____________________

>> Time taken (t):

  • 2 sec

______________________

>> Acceleration (a):

=> Change in velocity/Time taken

=> v - u/t

=> 8.33 - 11.11/2

=> -2.78/2

=> -1.39

______________________

∴ The acceleration of the bus is -1.39 m/s² or retardation of the bus is 1.39 m/s².

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