a bus decrease its speed from 80km h-1 to 60 km h-1 in 5s. find the acceleration of the bus
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Answered by
1
Answer:
acceleration = final velocity -initial velocity by time taken
i.e v-u÷t
80-60÷5
=20÷5
=4ms^2
Answered by
1
According to question,
Initial speed of bus=80x5/18
=22.22m/s
Final speed of bus=60x5/18
=16.66m/s
Time=5s
As we know,
v=u+at
22.22=16.66+a(5)
22.22-16.66=a(5)
5.56/5=a
a=1.12 m/s^2
Initial speed of bus=80x5/18
=22.22m/s
Final speed of bus=60x5/18
=16.66m/s
Time=5s
As we know,
v=u+at
22.22=16.66+a(5)
22.22-16.66=a(5)
5.56/5=a
a=1.12 m/s^2
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