a bus decrease its speed from 95 kilometers per hour to 90 kilometer per hour in 8 minutes. Find the acceleration of the bus
Answers
Answered by
0
initial velocity = 95 km/hr
= 95* 1000 / 60*60
= 26.38 m/s
final velocity = 90 km/hr
= 90*1000 / 60*60
= 25 m/s .
time t = 80 min = 80*60 = 4800s
a = v-u/t
a = 25-26.38/4800 = 0.0002827 m/s^2
Similar questions