Question

a bus decrease its speed from 95 kilometers per hour to 90 kilometer per hour in 8 minutes. Find the acceleration of the bus

Answer 1

initial velocity = 95 km/hr

= 95* 1000 / 60*60

= 26.38 m/s

final velocity = 90 km/hr

= 90*1000 / 60*60

= 25 m/s .

time t = 80 min = 80*60 = 4800s

a = v-u/t

a = 25-26.38/4800 = 0.0002827 m/s^2