Question

a bus decrease speed from 80know to 60know in 5 use the formula a =v-u/t​

Answer 1

Answer:

-4 m/s²

Explanation:

Given:

Initial velocity = 80 m/s (i)

Final velocity = 60 m/s (v)

Time = 5 seconds (t)

Acceleration =$\frac{v-u}{t}$

So substituting these values we get:

a = $\frac{60-80}{5}$

a = $\frac{-20}{5}$

a = $-4 m/s^{2}$

The acceleration of the bus is -4 m/s²

Using first equation of motion:

V=u+at

where:

V= final velocity

u = initial velocity

a = acceleration

t = time

substituting the values, we get:

60=80+a×5

-20 = 5a

a = $\frac{-20}{5}$

a = -4 m/s²

The acceleration of the bus is -4 m/s²