Question

A bus decreases it's speed from 72km/h to 54km/h in 10s.Calculate the acceleration of the bus

Answer 1

Answer:

-1.8 km h^-2

Explanation:

initial velocity (a) = 72 km h^-1

final velocity (b) = 54 km h^-1

time (t) = 10

acceleration = (b-a)/t

= (54-72)/10

=-1.8 km h^-2