A bus decreases it's speed from 80km/h to 50km/h in 4s. Find the acceleration of the bus?
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Answer:
u=80km/h for converting into m/s :--80*5/18= 4.45 m/s
v=50km/h for converting into m/s :--50*5/18= 2.78 m/s
t=4s
a=v-u/t
a=2.78-4.45/4
a=1.67/4
a= -0.4125m/s
Explanation: First we need to convert both km/h values to m/s value time is give in second so no need to change it then we should use acceleration formula and by substituting the values we will get the answer.
'v' is the final velocity
'u' is the initial velocity
't' is the time taken
'a' is the acceleration
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Explanation:
v=50 t=4second
u=80
v=u+at
50=80+a*4
-a*4=80-50
-a*4=30
-a=30/4
a= -7.5
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