a bus decreases it speed from 80km/hr to 60km/hr in 5sec find its acceleration
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change in speed /time=(80-60)/(3600×5)=20000/18000=20/18 m/sec
Answered by
1
given
u = 80 km /h or 80×5/18= 200/9 m/s
v = 60 km /h or 60 × 5/18 = 50/3 or 150/9 m/s
t= 5 sec
as
v = u + at
150/9 = 200/9 + 5a
150/9 - 200/9 = 5a
-50/9 = 5a
a = -50/9×1/5
= - 10/9 m/s^2
u = 80 km /h or 80×5/18= 200/9 m/s
v = 60 km /h or 60 × 5/18 = 50/3 or 150/9 m/s
t= 5 sec
as
v = u + at
150/9 = 200/9 + 5a
150/9 - 200/9 = 5a
-50/9 = 5a
a = -50/9×1/5
= - 10/9 m/s^2
prathameshgorapude:
thanks
you are welcome
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