A bus decreases its spee from 90km/hr to 36k/hr in 5 sec find acceleration of the bus
Answers
Answered by
0
a=V-U)/t
a. = 90-36)/5
a=10.8m/s^2
a. = 90-36)/5
a=10.8m/s^2
Answered by
0
Solution
Here;
v = 90 km/h
u = 36 km/h
t= 5 sec or 1/12 hr
a = v-u/t
= 90-36/1/12
= 54*12
= 648 km / h ^2
==============
☺☺
Here;
v = 90 km/h
u = 36 km/h
t= 5 sec or 1/12 hr
a = v-u/t
= 90-36/1/12
= 54*12
= 648 km / h ^2
==============
☺☺
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