A bus decreases its speed form 80kmh-1to 60kmh-1 in 5s find the acceleration of the bus
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Answered by
3
here is your answer
given :
initial velocity (u) = 80 km/hr = 80×(5/18) = 22.23 m/s
final velocity (v) = 60 km/hr = 60×(5/18) = 16.67 m/s
time taken (t) = 5 seconds
to find : acceleration
solution :
acceleration = change in velocity / time taken
acceleration = (v-u)/t
acceleration = (16.67-22.23)/5
acceleration = -1.112 m/s^2
so, the acceleration will be -1.112 m/s^2.
given :
initial velocity (u) = 80 km/hr = 80×(5/18) = 22.23 m/s
final velocity (v) = 60 km/hr = 60×(5/18) = 16.67 m/s
time taken (t) = 5 seconds
to find : acceleration
solution :
acceleration = change in velocity / time taken
acceleration = (v-u)/t
acceleration = (16.67-22.23)/5
acceleration = -1.112 m/s^2
so, the acceleration will be -1.112 m/s^2.
Answered by
5
Initial velocity = 80 km/hr = 22.22m/s
Final velocity = 60km/hr = 16.66m/s
Time = 5s
Acceleration = [16.66 - 22.22]/5
The acceleration of bus is -1.11 m s-2
Thanks!!❤
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