Question

A bus decreases its speed from 100km/ h to 50km/ h in 5s.Find the acceleration of the bus. step by step answer required​

Answer 1

Answer:

vi=100km/h

vf=50

a=?

t=5s

by putting values

a=(vf-vi)/t

50-100/5

-10

Answer 2

Question;-

A bus decreases its speed from 100km/ h to 50km/ h in 5s.Find the acceleration of the bus.

Required Answer:-

Given:-

• Initial velocity of the bus u = 100km/h
• Final velocity of the bus v = 50km/h
• Time t = 5s

To Find:-

• The acceleration a of the bus.

Solution:-

Here,

Initial velocity of the bus u = 100km/h = 27.7m/s

Final velocity of the bus v = 50km/h = 13.8m/s

Now, we know that:-

$\\ \underline{\boxed{\sf{v = u + at}}}$

Therefore:-

$\\ \sf{\implies{a = \dfrac{v - u}{t}}}$

Substituting the values:-

$\\ \sf{a = \dfrac{13.8m {s}^{ - 1} - 27.7m {s}^{ - 1} }{5s}}$

$\\ \sf{\implies{a = \frac{ - 13.9 {ms}^{ - 1} }{5s}}}$

$\\ \sf{\implies{a = \red{ - 2.78 {ms}^{ - 2}}}}$

Therefore, acceleration a = -2.78m/s^2

Here, the negative sign shows that the velocity is decreasing.