a bus decreases its speed from 80 kilometre per hour to 60 km per hour in 5 seconds find the acceleration of the bus
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u= initial velocity= 80 km/h = 22.2 m/s
v= final velocity = 60 km/h = 16.7 m/s
t= time = 5 s
a= acceleration = ?
a=v-u/t
a= 16.7-22.2/5
a= -5.5/5
Therefore, a=-1.1 m/s^2
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Answer:
given, initial velocity=u=80km/hr=22.2m/s
final velocity=v=60km/hr=16.7m/s
time=t=5s
we have to find acceleration,
a=(v-u) /t
a=(16.7-22.2) m/s/5s
so, a=-1.1 m/s^2
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