Science, asked by Bapan74, 8 months ago

a bus decreases its speed from 80 kilometre per hour to 60 km per hour in 5 second find the acceleration of the bus​

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Answered by Anonymous
4

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Answered by Mihir1001
7

\huge{\underline{\mathfrak{\textcolor{blue}{Answer :}}}}

\huge\boxed{ - 1.11 \: m {s}^{ - 2} }

\LARGE{\underline{\mathrm{\textcolor{red}{Step-by-step \:  \: explanation :}}}}

\LARGE{\underline{\mathtt{\textcolor{violet}{Given :-}}}}

initial speed of the bus, u = 80 km/h = \large{ \frac{200}{9} m/s}

final speed of the bus, v = 60 km/h = \large{ \frac{150}{9} m/s}

time taken, t = 5 s.

\LARGE{\underline{\mathtt{\textcolor{green}{To \:  \:  find :-}}}}

Acceleration of the bus.

\LARGE{\underline{\mathtt{\textcolor{teal}{Concept \:  \:  used :-}}}}

 \rightarrow Rate of change of velocity.

\LARGE{\underline{\mathtt{\textcolor{blue}{Solution :-}}}}

As per formula,

Acceleration,

\large{a =  \frac{v - u}{t} }

\large{ \:  \:  \:  \:  =  \frac{ \frac{200}{9} m {s}^{ - 1}  -  \frac{150}{9} m {s}^{ - 1} }{5 \: s} }

\large{ \:  \:  \:  \:  =  \frac{(150 - 200) \: m {s}^{ - 1} }{9 \times 5 \: s} }

\large{ \:  \:  \:  \:  =  \frac{ - 50}{9 \times 5} m {s}^{ - 2} }

\large{ \:  \:  \:  \:  =  -  \frac{10 \times 5}{9 \times 5} m {s}^{ - 2} }

\large{ \:  \:  \:  \:  =  -  \frac{10 \times 1}{9 \times 1} m {s}^{ - 2} }

\large{ \:  \:  \:  \:  =  - 1.11 \: m {s}^{ - 2} }

\LARGE{\underline{\mathtt{\textcolor{magenta}{Conclusion :-}}}}

acceleration, a =  - 1.11 \: m {s}^{ - 2} , there is negative ( - ) sign because the acceleration is to slow down the speed of the bus.

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