A bus decreases its speed from 80 km h–1 to 60 km h–1 in 5 s. Find the acceleration of the bus
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Answer:
a=(u-v) /t
here u is initial velocity and v is final velocity
a is acceleration and t is time
a=(80-60) /(5/60)
a=20×60/5
a=20×12
a=244
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Explanation:
Given, the initial velocity (u) = 80km/hour = = 22.22 m.s-1
The final velocity (v) = 60km/hour = = 16.66 m.s-1
Time frame, t = 5 seconds.
Therefore, acceleration (a) = =
= -1.112 m.s-2
Therefore, the total acceleration of the bus is -1.112m.s-2. It can be noted that the negative sign indicates that the velocity of the bus is decreasing.
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