Question

A bus decreases its speed from
80 km h–1 to 60 km h–1 in 5 s.
Find the acceleration of the bus.
Please answer the question I want to verify.

Answer 1

$\huge\mathbb\blue{Here\:is\:your\:answer}$

GIVEN,

$\implies$$\text{Initial Velocity=80km/hr=200/9m/s}$

$\text{Final Velocity=60km/hr=50/3m/s}$

$\text{Time taken=5 second}$

To Find;-

$\huge\mathbb\blue{Acceleration}$

Now,

$\text{Using first equation of motion}$

$a=v-u/t$

$50/3-200/9/5$

$Aceleration=-1.12m/s^-2$

$\huge\text{It is Retardation}$

$\huge\text\Blue{Some of the Useful formulae related to motion}$

• $S=ut+\frac{1}{2}at^2$

• $v^2=u^2+2as$

Thank You!

#Be barinly

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 80 km/h = 80 × 5/18 = 22.2 m/s

Final velocity, v = 60 km/h = 80 × 5/18 = 16.6 m/s.

Time taken, t = 5 seconds

To Find,

Acceleration, a = ???

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

v = u + at

⇒ 16.6 = 22.2 + a × 5

⇒ 16.6 - 22.2 = 5a

⇒  - 5.6 = 5a

⇒ - 5.6/5 = a

⇒ a = - 1.12 m/s²

Hence, the acceleration of the bus is - 1.12 m/s².