A bus decreases its speed from 80 km h−1to 60 km h−1 in 5 s. Find the acceleration of the bus.
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Answered by
706
u= initial velocity= 80 km/h = 22.2 m/s
v= final velocity = 60 km/h = 16.7 m/s
t= time = 5 s
a= acceleration = ?
a=v-u/t
a= 16.7-22.2/5
a= -5.5/5
Therefore, a=-1.1 m/s^2
Hope it helps u...
v= final velocity = 60 km/h = 16.7 m/s
t= time = 5 s
a= acceleration = ?
a=v-u/t
a= 16.7-22.2/5
a= -5.5/5
Therefore, a=-1.1 m/s^2
Hope it helps u...
Answered by
66
When a moving vehicle decreases its speed by applying breaks, the phenomenon is called deacceleration.
In such a case we use the formula for deacceleration = (initial speed – final speed)/time.
The time given is in seconds which can be expressed in hours as 5/3600hrs or 1/720hrs.
Hence the deacceleration in this case will be, (80-60)/(1/720) km-hr-2 = 14400 km-hr-2
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