Question

A bus decreases its speed from 80 km/h to 50 km/h in 5 s. Find the acceleration of the bus.

Answer 1

Answer:

Answer is 6

by the formula of acceleration v-u

T

Answer 2

Answer :-

-1.6m/s^2

Explanation :-

Given :

Initial velocity of the bus,u =  80km/hr => 22.22m/s

Final velocity of the bus = 50km/hr => 13.88

Time taken = 5s

To Find :

Acceleration,a = ?

Solution :

We know,

$\boxed{\sf{}v=u+at}$

here,

v is the final velocity,

u is the initial velocity,

a is the acceleration and,

t is the time taken.

Put their values and solve it,

$\sf{}:\implies 13.88=22.22+a\times 5$

$\sf{}:\implies 13.88-22.22=a\times 5$

$\sf{}:\implies -8.34=a\times 5$

$\sf{}:\implies -\dfrac{8.34}{5}=a$

$\sf{}\therefore a=-1.6m/s^2$

Therefore,acceleration is equal to -1.6m/s^2

Know more :

There are three equation of motion,

$\sf{}First\ equation\ of\ motion: \ v=u+at$

$\sf{}Second\ equation\ of\ motion: \ s=ut+\dfrac{1}{2}at^2$

$\sf{}Third\ equation\ of\ motion: \ v^2=u^2+2as$