A bus decreases its speed from
80 km h to 60 km h in 5 s.
Find the acceleration of the bus.
Answers
Answered by
3
u=80*5/18=22m/s
v=60*5/18=17m/s
a=v-u/t
=(17-22)/5
=-5/5
a =-1
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Answered by
1
Given:-
Initial velocity ,u = 80km/h
Final velocity ,v = 60km/h
Time taken ,t = 5 s
To Find:-
Acceleration ,a
Solution:-
⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question
Firstly we change the unit of velocity .
Initial velocity ,u = 80 × 5/18 = 400/18 = 22.22 m/s
Final velocity ,v = 60 × 5/18 = 300/18 = 16.66
As we know that acceleration is defined as the rate of change in velocity
a = v-u/t
where,
v denote final velocity
u denote initial velocity
t denote time taken
a denote acceleration
Substitute the value we get
⟹ a = 16.66-22.22/5
⟹ a = -5.56/5
⟹ a = -1.12 m/s²
here, negative sign show retardation
Hence, the acceleration of the bus is approximately 1.12 m/s²
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