Question

A bus decreases its speed from
80 km h to 60 km h in 5 s.
Find the acceleration of the bus.​

Answer 1

u=80*5/18=22m/s

v=60*5/18=17m/s

a=v-u/t

 =(17-22)/5

 =-5/5

a =-1

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Answer 2

Given:-

Initial velocity ,u = 80km/h

Final velocity ,v = 60km/h

Time taken ,t = 5 s

To Find:-

Acceleration ,a

Solution:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question

Firstly we change the unit of velocity .

Initial velocity ,u = 80 × 5/18 = 400/18 = 22.22 m/s

Final velocity ,v = 60 × 5/18 = 300/18 = 16.66

As we know that acceleration is defined as the rate of change in velocity

a = v-u/t

where,

v denote final velocity

u denote initial velocity

t denote time taken

a denote acceleration

Substitute the value we get

⟹ a = 16.66-22.22/5

⟹ a = -5.56/5

⟹ a = -1.12 m/s²

here, negative sign show retardation

Hence, the acceleration of the bus is approximately 1.12 m/s²