A bus decreases its speed from 80 km/h to 60km/h in 5second Find acceleration and distance?
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Hey frnd
Here is the answer :
Acc. (a)=change in velocity (∆v)/time
a = 22.25 m/s - 16.70 m/s÷5 sec
a = 5.55/5
.°. a = 1.11 m/s^2
Dist. (s)=5.55×5=27.75m
Here is the answer :
Acc. (a)=change in velocity (∆v)/time
a = 22.25 m/s - 16.70 m/s÷5 sec
a = 5.55/5
.°. a = 1.11 m/s^2
Dist. (s)=5.55×5=27.75m
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