A bus decreases its speed from 80 km ke to 60 kiek in .5s. Find the acceleration of the bus ?
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Acceleration a = (V - U) / t
Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.2 m/sec
Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.6 m/sec
Acceleration a = (V - U) / t
= (16.6 - 22.2)/5
= -5.6/5
= -1.12 m/s2
Negative sign indicates that the velocity is decreasing.
Therefore, the acceleration of the bus that decreases its speed from 80 kilometers per hour to 60 km per hour in 5 seconds is -1.12m/s2
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