A bus decreases its speed from 80km/h to 50 km/h in 5 sec find its acceleration of the bus
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acceleration = difference of velocity / time
1 km/hr = 1000/3600 m/s.
= 5/18 m/s
a = (80-50)×5/5×18. m/s^2
a = 30/18 m/sec^2
a = 1.66 m/sec^2
1 km/hr = 1000/3600 m/s.
= 5/18 m/s
a = (80-50)×5/5×18. m/s^2
a = 30/18 m/sec^2
a = 1.66 m/sec^2
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