Question

A bus decreases its speed from 80km/h to 50km/h in 4 seconds. Find the acceleration of the bus.

Answer 1

innitial velocity, u = 80kmph = 200/9 m/sfinal velocity, v = 50kmph = 125/9 m/stime, t = 4 seconds acceleration, a = v-u/t (change in velocity per unit time) therefore, a= (125/9-200/9)/4a= (-75/9)/4a= -75/9 x 1/4 a= -75/36 m/s2

* u can futher divide it

Answer 2

Hey friend
here is your answer

initial velocity ( u ) = 80km/hr or (200/9) m/sec
final velocity ( v ) = 50 km/hr or (125/9) m/sec
time ( t ) = 4 second


$acceleration = \frac{v - u}{t} \\ acceleration = \frac{ \frac{125}{9} - \frac{200}{9} }{4} \\ acceleration = \frac{ - 75}{36} \\ acceleration = - 2.0833 \: m \: {sec}^{ - 2}$

glad to help you
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