A bus decreases its speed from 80km/h to 60km/h in 10sec. Find the acceleration of the bus. also find the distance covered by bus
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u=80km/hr
v=60km/hr
t=10s
a=?
v=u+at
60=80=a(10)
60-80=a(10)
-20=a(10)
a= -2m/s2
s=ut+1/2at2
=80×10+1/2(-2)2
=800+(-2)
=798
v=60km/hr
t=10s
a=?
v=u+at
60=80=a(10)
60-80=a(10)
-20=a(10)
a= -2m/s2
s=ut+1/2at2
=80×10+1/2(-2)2
=800+(-2)
=798
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