Question

A bus decreases its speed from 80km/h to 60km/h in 5s.Find the acceleration of the bus​

Answer 1

Answer:

Acceleration a = (V - U) / t

Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.2m/sec

Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.6m/sec

Acceleration a = (V - U) / t

= (16.6 - 22.2)/5

= -5.6/5

= -1.12 m/s2

Negative sign indicates that the velocity is decreasing.

Therefore, the acceleration of the bus that decreases its speed from 80 kilometers per hour to 60 km per hour in 5 seconds is -1.12m/s2

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Answer 2

$\large\text{\fcolorbox{aqua}{lime}{\red{Given:-}}}$

U= initial velocity= 80 km/h = 22.2 m/s

v= final velocity = 60 km/h = 16.7 m/s

t= time = 5 s

$\large\text{\fcolorbox{aqua}{gold}{\red{Find:-}}}$

We have to find a= acceleration = ?

$\large\text{\fcolorbox{aqua}{yellow}{\red{Formula:-}}}$

$\bold{\blue{\fbox{\sf{v = u+at}}}}$

a = v – u/t

a = 16.7 – 22.2/5

= -5.5/5

Therefore, acceleration a = -1.1 m/s2

The negative sign implies that the velocity is decreasing.