Question

a bus decreases its speed from 80kmph to 60 kmph in 5s find acceleration of bus​

Answer 1

Explanation:

Initial speed u=80 km/h=80× 5÷18 =22.22 m/s

Final speed v=60 km/h=60× 5÷18 =16.67 m/s

Using v=u+at

16.67=22.22+α×5

⟹ a=−1.1 m/s²

hope it is helpful to you (◍•ᴗ•◍)

Answer 2

Answer:

-1.1111m/s^2

Explanation:

acceleration is change in velocity/time,  final vel is 60km/h . initial vel is 80km/h. change in vel is 60-80 = -20 km/h , convert this value to m/s and it gives you -5.55555m/s, now divide this velocity over the time it took to go from the initial/original velocity to the final velocity and it would be -5.555/5 = -1.1111ms^-2 (this is negative acceleration or deceleration)