Question

A bus decreases its speed from 90km/h to 72km/h in 5 seconds. Find the acceleration of bus.

Answer 1

hope it helps...........

Answer 2

Answer:

Acceleration of bus $=-1m/s^{2}$

Explanation:

Initial velocity of bus $=90km/hr$

                                  $= 90 *\frac{5}{18} m/s$

                                   $= 25m/s$

Final velocity of bus $= 72km/hr$

                                  $= 72* \frac{5}{18} m/s$

                                  $= 20m/s$

Acceleration is the rate of change of velocity.

$Acceleration = \frac{Final .velocity - Initial. velocity}{Time}$

$Acceleration = \frac{20-25}{5}$

$Acceleration = \frac{-5}{5}$

$Acceleration = -1m/s^{2}$

Therefore, acceleration of bus $=-1m/s^{2}$ and -ve sign indicates retardation of bus.

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