A bus decreases its speed from 90km/hr to 36km/hr in 10 seconds. Find the acceleration of the bus in m/s2.
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Given :
• Initial Velocity (u) = 90 km/hr
• Final Velocity (v) = 36 km/hr
• Time (t) = 10 seconds
To Find :
• Acceleration of the bus
Solution :
First of all let's convert given velocities into m/s
• 90 km/ hr
→ 90 × 5/18
→ 5 × 5
→ 25 m/s
• 36 km/hr
→ 36 × 5/18
→ 2 × 5
→ 10 m/s
Now,
★ Acceleration = Final Velocity - Initial Velocity/Time taken
★ a = v - u/t
→ a = 10 - 25/10
→ a = -15/10
→ a = -1.5 m/s²
Acceleration of the bus is -1.5 m/s²
Since the speed of the bus is decreasing, therefore the value of the acceleration is in negative.
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