a bus increase its speed from 54km/h to 72km/h in 5seconds calculate acceleration
Answers
Answer:
Explanation:
Acceleration = Change in velocity / Time
= v - u / t
72km/h = 72 × 5 / 18 m/s = 20m/s
54km/h = 54 × 5 / 18m/s = 15m/s
Acceleration = 20-15 / 10
= 5 /10
= 0.5 m/s²
To find distance we use the formula
v² = u² + 2aS here v is the final velocitiy (72km/h)
u is the initial velocity(54km/h)
a is the acceleration
S is the distance
20² = 15² + 2 × 0.5 × S
400 = 225 + 1×S
400 - 225 = S
S = 175 m
Therefore distance = 175m
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Answer:
Explanation:
u=54km/hr=54×(5÷18)
=15m/s
v=72km/hr=72×(5÷18)
=20m/s
t=5 sec
a=(v-u)/t
=(20-15)/5
=5/5=1
acceleration=1m/s²