Question

A bus increases its speed from 30m/s to 50m/s in 5seconds find the accelaration of the bus​

Answer 1

Final velocity(v) = 50m/s,

Initial velocity (u) = 30m/s , time = 5s

∴ Acceleration = v - u / t = 50-30/5 = 20/5 = 4m/s^2

Answer 2

Given :-

A bus increases it's speed from 30 m/s to 50 m/s in 5 seconds .

Required to find :-

• Acceleration of the bus ?

Concept used :-

• Acceleration

Formula used :-

$\huge{\dagger{\boxed{\rm{Acceleration = \dfrac{ \Delta v}{ \Delta t }}}}}$

Solution :-

Given that :-

A bus increases it's speed from 30 m/s to 50 m/s in 5 seconds

From the above we can conclude that

• Initial velocity of the bus = 30 m/s

• Final velocity of the bus = 50 m/s

• Time = 5 seconds

We need to find the acceleration of the bus

Now recall the definition of the acceleration

Acceleration is the change in the velocity in a unit of time .

This is represented as ;

$\tt{ Acceleration = \dfrac{ Change \; in \; velocity }{ Change \; in \; time }}$

$\implies{\tt{ Acceleration = \dfrac{ \Delta v }{ \Delta t }}}$

Here,

∆ - This is known as " Delta ".

∆ - This represents " Change "

Hence

Change is velocity is defined as the difference between the final velocity and initial velocity

So,

∆v = v - u

However ,

∆t = t

Substitute this in the formula

$\rm{ Acceleration = \dfrac{ v - u }{ t } }$

using the this formula we can solve the above question .

$\longrightarrow{\sf{Acceleration = \dfrac{ 50 \; m/s - 30 \; m/s }{ 5 \; s }}}$

$\longrightarrow{\sf{ Acceleration = \dfrac{ 20 \; m/s }{ 5 \; s }}}$

$\longrightarrow{\sf{ Acceleration = 4 \; m/{s}^{2} }}$

Therefore ,

Acceleration of the bus = 4 m/s²

Additional Information :-

1. Final velocity is denoted by the letter v .

2. Initial velocity is denoted by the letter u .

3. The S.I. unit of acceleration is m/s² .

4. If the velocity of the body is constant then the acceleration of the body is zero .

5. Acceleration can be both positive and negative .