Question

A bus increases its speed from 36 km/h to 72 km/h in 10 second then distance traveled by bus during this time is
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Answer 1

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A bus increases its speed from 36 km/h to 72 km/h in 10 second then distance traveled by bus during this time is 150m

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Explaination :-

➮ Given :-

• initial velocity, u = 36 km/h
• final velocity, v = 72 km/h
• time, t = 10s

➮ To find :-

distance travelled by bus

➮ Conversion :-

convert km/h to m/s

We know,

1 km/h = 5/18 m/s

➝ 36 km /h = 10 m/s

36 × 5/18 = 5 × 2 = 10 m/s

➝ 72 km/h = 20 m/s

72 × 5/18 = 4 × 5 = 20 m/s

➮ Solution :-

using first equation of motion that is

$\longrightarrow \bf v = u + at$

$\longrightarrow \sf 20 = 10 + a(10)$

$\longrightarrow \sf 20 - 10 = 10a$

$\longrightarrow \sf 10 = 10a$

$\longrightarrow \boxed{ \sf a = 1 {ms}^{ - 2} }$

to find distance

we have to use 2rd equation of motion,

that is,

$\longrightarrow \bf s = ut + \frac{1}{2} {at}^{2}$

$\longrightarrow \sf s = (10)(10) + \frac{1}{2} \times (1) {(10)}^{2}$

$\longrightarrow \sf s = 100 + \frac{1}{ \cancel 2} \times \cancel{ 100}$

$\longrightarrow \sf s = 100 + 50$

$\longrightarrow \boxed{ \bf s = 150m}$

Thus, the distance covered in 10s is 150m

Answer 2

Answer :

➥ The Distance travelled by a bus = 150 m

Given :

➤ Initial velocity of a bus = 36 km/hr

➤ Final velocity of a bus = 72 km/hr

➤ Time taken by a bus = 10 sec

To Find :

➤ Distance travelled by a car = ?

Required Solution :

✒ To find the Distance travelled by a bus, first we need to convert the Initial velocity and Final velocity of a bus km/hr to m/s, to convert the Initial velocity and Final velocity multiply the speed value by 5/18. after that we will find Acceleration of a bus, After all this we will find the Distance travelled by a bus.

◈ Initial velocity = 36 km/hr

→ Initial velocity = 36 × 5/18

→ Initial velocity = 2 × 5

→ Initial velocity = 10 m/s

◈ Final velocity = 72 km/hr

→ Final velocity = 72 × 5/18

→ Final velocity = 4 × 5

→ Final velocity = 20 m/s

❍ In the question, Final velocity is given, Initial velocity and Time taken is also given but we have to find the Acceleration of a bus.

This is given to find Acceleration of a bus because of the first equation of motion:

★ v = u + at ★

So, we are provided with two elements used in the formula:

• Final velocity of a bus (v) = 20 m/s
• Initial velocity of a bus (u) = 10 m/s
• Time taken of a bus (t) = 10 sec

We have to find the Acceleration of a bus.

From first equation of motion

⇒ v = u + at

⇒ 20 = 10 + a × 10

⇒ 20 = 10 + 10a

⇒ 20 - 10 = 10a

⇒ 10 = 10a

⇒ 10/10 = a

⇒ 1 = a

⇒ a = 1 m/s²

Now, we have three elements used in formula. Initial velocity, Time taken, and Acceleration of a bus.

• Initial velocity of a bus = 10 m/s
• Time taken by a bus = 10 sec
• Acceleration of a bus = 1 m/s²

We can find Distance travelled by a bus by using the second equation of motion which says:

★ s = ut + ½ at² ★

Here,$\:$

• s is the Distance in m.
• u is the Initial velocity in m/s
• t is the Time taken in second.
• a is the Acceleration in m/s².

✎ So, let's find Distance (s) !

From second equation of motion

⇛ s = ut + ½ at²

⇛ s = 10 × 10 + ½ 1 × 10²

⇛ s = 100 + ½ + 1 × 100

⇛ s = 100 + ½ + 100

⇛ s = 100 + 1 × 50

⇛ s = 100 + 50

⇛ s = 150 m

║Hence, the Distance travelled by a bus is 150 m.║