A bus increases its speed from 36 km/hr to 90km/hr in 10 seconds and stop in 5 seconds after applying brakes. Calculate acceleration in both cases
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good morning dear!
first of all we should know about acceleration. Basically rate of change of velocity with respect to time is called velocity.
therefore,
in first case a = ∆v/t
a = v2-v1/t
a = (90 × 5/18 - 36 × 5/18)/ 10. { to convert km/hr into m/s we have to multiply by 5/18}
in second case, v2 becomes zero
therefore,
a = (0 × 5/18 - 90 × 5/18)/ 5
hope it will help you.
have a nice day.
first of all we should know about acceleration. Basically rate of change of velocity with respect to time is called velocity.
therefore,
in first case a = ∆v/t
a = v2-v1/t
a = (90 × 5/18 - 36 × 5/18)/ 10. { to convert km/hr into m/s we have to multiply by 5/18}
in second case, v2 becomes zero
therefore,
a = (0 × 5/18 - 90 × 5/18)/ 5
hope it will help you.
have a nice day.
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