Question

A bus increases its speed from 36km/h to 72km/h in 10 seconds. It’s acceleration is ​

Answer 1

Explanation:

Final velocity = 72 km = 72000m

Initial velocity = 36 km = 36000m

Acceleration (a) = (Final velocity {v} - initial velocity {u}) /time

= 72000 - 36000/ 10

= 36000/10

= 3600 m/s²

{Note - We have converted all the units in SI units and then calculated, amd our answer also follows the SI system}

Answer 2

Answer:

1m/s^2

Explanation:

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We have

u = 36 km/h

= 10 m/s

v = 72 km/h

= 72× 100 / 60 × 60

= 7200/ 360

= 20 m/s

t = 10 second

We know

A = V- U / t

= 20 - 10 / 10

= 1 m/s ^2

Hence the acceleration of the bus after increasing it's speed is 1 m/s^2

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