Question

A bus increases its speed from 36km,/h to 72km/h in 10seconds. Its acceleration is ......

Answer 1

$a = \frac{v - u}{t}$

$a = \frac{72 - 36}{10}$

$a = \frac{36}{10}$

$a = 3.6 \: {ms}^{ - 1}$

Here,

a= acceleration

v= final velocity

u= initial velocity

t= time

Answer 2

Answer:

The initial velocity u =36 km/h=10 m/sthe Final velocity v =72 Km/h = 20 m/sThe time period t = 10 s using first equation of motionv – u = atwherev is the final velocityu is the initial velocitya is the accelerationt is the time period putting the value of v,u,t in the equation, we get20 -10 =a ×10a = 1 m/s2

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