Physics, asked by Anshica18, 8 months ago

A bus increases its speed from 500 m/s to 900m/s in 4s. Find the acceleration.​

Answers

Answered by naveenyadu27
0

Answer:

100 m/s².

Explanation:

V = u + a×t

900 = 500 + a × 4

900 - 500 = a × 4

400/4 = a

100 = a Ans.

Another method

simply minus the initial velocity (u) with final velocity (v) and divide it by time (t)..

Answered by RISH4BH
64

Given:-

  • A bus increases its velocity from 500m/s to 900m/s.
  • It took a time of 4s.

To Find:-

  • The acclⁿ of the bus .

Formula Used:-

We know that acceleration is defined as the rate of change of velocity. So , mathematically,

\large{\underline{\boxed{\red{\sf{\dag accl^n=\dfrac{v-u}{t}=\dfrac{\Delta v}{\Delta t}}}}}}

Answer:-

Here ,

  • Initial Velocity =500m/s.
  • Final Velocity = 900m/s.
  • time = 4s.

So by putting the respective values in the above formula stated, we have :

➥ acclⁿ = ∆v / ∆t = v - u / t .

➥ acclⁿ = 900m/s - 500m/s / 4.

➥ acclⁿ = 400m/s / 4 .

➥ acclⁿ = 100m/s².

Hence the acceleration is 100m/.

Note :- When the velocity of a body decreases with the increase in time then it is called retardation or the deacceleration.

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