A bus increases its speed from 500 m/s to 900m/s in 4s. Find the acceleration.
Answers
Answered by
0
Answer:
100 m/s².
Explanation:
V = u + a×t
900 = 500 + a × 4
900 - 500 = a × 4
400/4 = a
100 = a Ans.
Another method
simply minus the initial velocity (u) with final velocity (v) and divide it by time (t)..
Answered by
64
Given:-
- A bus increases its velocity from 500m/s to 900m/s.
- It took a time of 4s.
To Find:-
- The acclⁿ of the bus .
Formula Used:-
We know that acceleration is defined as the rate of change of velocity. So , mathematically,
Answer:-
Here ,
- Initial Velocity =500m/s.
- Final Velocity = 900m/s.
- time = 4s.
So by putting the respective values in the above formula stated, we have :
➥ acclⁿ = ∆v / ∆t = v - u / t .
➥ acclⁿ = 900m/s - 500m/s / 4.
➥ acclⁿ = 400m/s / 4 .
➥ acclⁿ = 100m/s².
➤Hence the acceleration is 100m/s².
Note :- When the velocity of a body decreases with the increase in time then it is called retardation or the deacceleration.
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