Question

A bus increases its speed from 54 km/h to 90 km/h in 5 s, then acceleration of the bus is * 36 m/s² 2 m/s² 10 m/s² 10 km/ h
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Answer 1

Explanation:

initial velocity vi=54km/h=15m/s

final velocity vf=90km/h=10m/s

time t=5sec

acceleration=?

formula to calculate a is

vf-vi/t=a

a=25-15/5

a=2m/s2

Answer 2

T = 5s

u (initial velocity) = 54km/h = 15m/s

$54 \times \frac{5}{18} = 15$

v (final velocity) = 90km/h = 25m/s

$90 \times \frac{5}{18} = 25$

$a = \frac{v - u}{t}$

$= \frac{25 - 15}{5} = \frac{10}{5} = 2$

Acceleration = m/s2