Question

A bus increases its speed from 54 Km/hr to 90 Km/hr in 10 seconds, Find its acceleration.​

Answer 1

$\small\star\underline\bold\red{Given:-}$

• Initial speed of bus (u) = 54 km/h = 15 m/s
• Final speed of bus (v) = 90 km/h = 25 m/s
• Time taken = 10 seconds.

$\small\star\underline\bold\red{Solution:-}$

$\small\fcolorbox{red}{yellow}{ Acceleration = (v-u)/ t }$

i.e.

Acceleration of bus = $\frac{25-15}{10}$ = 1 m/s²

Answer 2

The acceleration is 1 m/s².

Given - Speed and time

Find - Acceleration

Solution - The acceleration will be calculated using the formula -

v = u + at

Converting speed in km/hr to m/s.

Initial speed = 54*5/18

Initial speed = 3*5 m/s

Initial speed = 15 m/s

Final speed = 90*5/18

Final speed = 5*5

Final speed = 25 m/s

Keep the values in formula to find the value of acceleration.

$25 = 15 + a \times 10$

$a \times 10 = 25 - 15$

$a \times 10 = 10$

$a = \frac{10}{10}$

$a = 1 \: \frac{m }{ {s}^{2} }$

Hence, the acceleration is 1 m/s².

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